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Journal of Applied Sciences

Year: 2005 | Volume: 5 | Issue: 5 | Page No.: 859-861
DOI: 10.3923/jas.2005.859.861
Killing Forms and Applications
Md. Haider Ali Biswas, Moslehuddin Ahmed and Mohammad Jalal Ahammad

Abstract: Characterizations of Semi-simple algebra were initiated by Cartan. In recent years, semi-simple Lie algebras have been characterized with the help of Killing forms. In this study we have made an attempt to define generalized killing forms and have applied these to the question of existence of Lagrangians in a physical system.

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Md. Haider Ali Biswas, Moslehuddin Ahmed and Mohammad Jalal Ahammad, 2005. Killing Forms and Applications. Journal of Applied Sciences, 5: 859-861.

Keywords: semi-sample Algebra, Yang-mills equation, Euler-lagrange equation, lagrangians, lie algebra, killing forms and solvable lie groups

INTRODUCTION

Killing Forms (KFs) play a very important role in characterizing semi-simple algebras[1]. One of these schemes is the Cartan’s criterion that states that Lie algebra is semi-simple if and only if its KF is non-degenerate. Recall: a Lie algebra has an extra structure called the Lie bracket or Lie product which has close link with calculus of manifolds.

BASIC DEFINITIONS AND USEFUL RESULTS

Bilinear forms: Let Vn (F) be an n-dimensional linear space defined over the scalar field F. Then the mapping:

with the following axioms is called a bilinear form:

(i) T (αu1+βu2,v) = αT(u1, v), +βT(u2, v)
(ii) T (u, γv1+δv2) = γ T (u, v1) + δT (u, v2)

for all u1, u2, v1, v2 ∈Vn (F) and α, β, γ, δ ∈F

The rank of a bilinear form T on Vn (F) denoted by rank (T) is defined to be the rank of any matrix representation of T. We say that T is degenerate or non-degenerate according as whether rank (T) < dim (V) or rank (T) = dim (V).

A bilinear from T on a linear space Vn (F) is said to be symmetric if:

Theorem 1: Let T: IRn x IRn→IR be a bilinear form and let A be a matrix representation of T. Then A is symmetric if and only if T is symmetric in IRn.

Theorem 2: Let T be a symmetric bilinear form on a linear space Vn (F). Then Vn has a basis {vi}ni = 1 in which T is represented by a diagonal matrix i, e. T (vi, vj) = 0 if i ≠ j.

Quadratic forms: A mapping q: Vn(F)→F is called a quadratic form if q(v) = T(v, v) for some symmetric bilinear form T on Vn. If T is represented by a symmetric matrix A = (aij) then q: Vn(F)→F is represented in the form:

Note that, if A is diagonal, then it has the diagonal representation

That is, the quadratic polynomial representing 'q' will contain no “cross-product” terms. For example, consider the mapping q: IR 2→IR over the scalar field IR, defined by:

Then q (x, y) satisfies all the conditions of quadratic forms. The symmetric matrix A of this quadratic form is and in case h = 0 i.e. A is diagonal then

Killing forms[2-4]: Let G be a Lie algebra Suppose X,Y are arbitrary elements of G. Then the operator.

defined by adX(Y) = [X,Y] is a linear transformation.

Recall: If V is a vector space over the field F, Then a mapping T of V(F) into V(F) is called a linear transformation (or a linear operator) if T satisfies the following conditions:

(i) If v1, v2 ∈ V(F), then T (v1 + v2) = Tv1 + Tv2
(ii) If v1∈V(F), s ∈ F, then T(sv1) = sTv1

To see that adX: G→G defined by adX(Y) = [X,Y] is a linear transformation.

We calculate: adX(Y+Z) = [X,Y+Z], ∀ Y, Z ∈ G

Hence the operator adX: G→G is a linear transformation.

Note that X→adX is a representation of the Lie algebra G with G itself considered as linear space of the representation. The representation adX, called the adjoint representation, always provides a matrix representation of the algebra. For example, the adjoint representation of the algebra of SO(3) is given by:

(Mi)jk = Cjik =∈ikj = - ∈ijk, where, ∈ijk is antisymmetric in i,k.

Thus the matrices

with structure constants ∈ikl being antisymmetric in i and k given by:

are also the matrices of the adjoint representation.

The Killing form of a Lie algebra G is the symmetric bilinear form:

If {Ei}ni = 1 is a basis in G for then gij = K (Ei, Ej)= Cris Csjr is called the metric tensor for G where, the Ckis are the structure constants of G.

A GENERALIZATION OF KILLING FORMS

We consider a connected and compact Lie group with corresponding Lie algebra G0 having dim (G0) = l0 and any arbitrary Lie algebra G1 with dim (G1) = l1. Then the direct sum G = G 0 ⊕ G1 is a Z 2-graded Lie algebra. Suppose is a basis of G with dim (G) = l0 + l1. Then form by the mapping

(1)

Now we define the generalized Killing form by symmetric bilinear form:

where:

is called a degree of Xl. Further Xl is said to be even or odd, respectively if d1 = 0 or 1.

APPLICATION OF KFs

Invariant quadratic forms defined originally by the then algebraists have close link with KFs of differential geometry[5,6]. Cartan's criterion on semi-simplicity of algebra may be stated in an equivalent form: a Lie algebra G is semi-simple if and only if det (gij)≠ 0 where, gij is the metric tensor for G. Thus we see that semi-simple algebras always admit a non-degenerate invariant quadratic form on G. The general result stated above on KFs may be used to test a set of differential equations for the existence of a Lagrangian of a physical system.

Let G be a 2-dimensional non-abelian solvable Lie group with corresponding Lie algebra G spanned by the basis {X1, X2},

Where:

with commutation relation

We consider the Yang-Mills equations associated with G:

(2)

with Da, the covariant derivative associated with G-valued connection γa and curvature Fab representing Yang-Mills potentials and fields, respectively. The algebra involved here has a degenerate KF since det(gij) = 0. On the other hand, consider the SL(2,C) (C is set of complex numbers) algebra with a basis {X1,X2, X3} given by:

Analogously, we define the Yang-Mills field equations associated with the above 3-dimensional algebra:

(3)

The algebra involved here has a non-degenerate KF since det(gij)≠0. Applying variational principle on principal fibre bundles, we see that the above Yang-Mills equations associated with the Lie group G under consideration are exactly the Euler-Lagrange differential equations[7]. Since the corresponding Lie algebra G admits a non-degenerate KF. But the equation (2) fails to be Euler-Lagrange equations since the corresponding Lie algebra G does not admit a non-degenerate KF.

CONCLUSION

Let us consider the GKF. It is possible to require that K* acts on the sub-space G0 only. Consequently K* reduces to the usual Killing form for the Lie algebra G0. Recall: G0 is compact in the sense of the group K is negative definite and hence G0 is semi-simple. It indicates that a graded Lie algebra G can be made to possess a GKF which guarantees that a Lagrangian must exist for the theory under consideration.

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